Web30 mrt. 2024 · Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.
If a b c d e are the AP then find the values of a-4b+6c-4d+e
Web1 jan. 2024 · It's impossible that a = b = c = d = 1. Thus, a b c d ≥ 2 and e = a + b + c + d a b c d − 1 ≤ 5. The equality occurs for ( a, b, c, d, e) = ( 1, 1, 1, 2, 5). For a proof of the last inequality we can use the following reasoning. Let a = 1 + x, b = 1 + y, c = 1 + z and d = 2 + t. Thus, x, y, z and t are non-negatives and we need to prove that: Web19 jan. 2024 · If a, b, c, d, e and f are in AP, then e-c is equal to (a) 2 (c - a)(b) 2f-d)(c) 2 (d-c)(d) d-c . If a, b, c, d, e and f are in AP, then e-c is equal to. (a) 2 (c - a) (b) 2f-d) (c) … simonmed corporate address
If a,b,c are in A.P and a, b, din G.P., then a, a b, d c will be in
WebCorrect option is D) For the given sets, (A∪B)= { a,b,c,d,e,g } (Combination of all elements of both sets) Clearly, elements of C are a part of A∪B as well, So, C⊂(A∪B) And, (A∩B)= { a,c,e } (Common elements of both sets ) As the elements of C are not completely a part of A∩B , Option B is not True. Also, (A∪C)= { a,b,c,d,e,g } Clearly, (A∪B)=(A∪C) Web6 aug. 2024 · Given that a,b,c,d,e are in Arithmetic progression. that means first term a1=a let common difference be D then we can rewrite each term using nth term formula as: an=a1+ (n-1)d a b=a+x c=a+2x d=a+3x e=a+4x Now plug these values into given expression a-4b+6c-4d+e a-4b+6c-4d+e =a-4 (a+x)+6 (a+2x)-4 (a+3x)+ (a+4x) =a-4a … WebCorrect option is D) For the given sets, (A∪B)= { a,b,c,d,e,g } (Combination of all elements of both sets) Clearly, elements of C are a part of A∪B as well, So, C⊂(A∪B) And, … simon med citrus tower blvd